What is the ratio P1/P2P1/P2 of their power dissipations if the same current passes through each resistor

This question is incomplete, the complete question  is;

Resistors 1 and 2 are connected to identical batteries, resistor 1 dissipates 4.0 times more power than resistor 2

What is the ratio P1/P2of their power dissipations if the same current passes through each resistor

the ratio P₁/P₂ of their power dissipations is 0.25

Explanation:

Given the data in the question;

= --------------let this be equation 1

= -----------------let this be equation 2

P₁ = V²/R₁

P₁ = 4P₂

so

P₁ = V²/R₁ = 4( V²/R² )

now, form the above equation;

R₁ = R₂/4

using equation 1, we get;

P₁ =  

P₂ =  

Hence;

P₁ =  ( R₂/4)

P₁ =   × ( R₂/4)

P₁ = (1/4) P₂ or 0.25

Therefore; the ratio P₁/P₂ of their power dissipations is 0.25

which statement about this sum is true? −245+2.7

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.