Physics, 25.02.2021 21:30 runninglovexoxo
A snowflake (1.5 x 10-9) falls to Earth’s surface under gravity (9.8 m/s^2). What is the force of the snowflake?
A. 1.5 x 10-8 N
B. 6.5 x 109 N
C. 1.5 x 1010 N
D. 0 N
Answers: 3
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The x-coordinate of a particle in curvilinear motion is given by x = 3.1t3 - 4.9t where x is in feet and t is in seconds. the y-component of acceleration in feet per second squared is given by ay = 2.3t. if the particle has y-components y = 0 and vy = 5.0 ft/sec when t = 0, find the magnitudes of the velocity v and acceleration a when t = 1.8 sec. sketch the path for the first 1.8 seconds of motion, and show the velocity and acceleration vectors for t = 1.8 sec. answers: v = ft/sec a = ft/sec2
Answers: 2
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Physics, 22.06.2019 06:30
Apebble is thrown into a calm lake, ripples are formed from the center and move outward. the water particles in the lake travel in a circular pattern that moves up and down on the surface of a lake, and the energy travels a) diagonally. b) downward. c) horizontally. d) upward.
Answers: 2
A snowflake (1.5 x 10-9) falls to Earth’s surface under gravity (9.8 m/s^2). What is the force of th...
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