Calcula la densidad y peso específico de 500g de alcohol metilico usado como anticongelante vehicular que ocupan 632 cm3

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Explanation:

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density =  0.791 g/cm^3

specific weight =  775 g /(cm^2 s^2)

Explanation:

Recall that density is defined as: Mas / Volume

Then, in our case:  density = 500 g / 632 cm^3 = 0.791 g/cm^3

Recall that the specific weight is defined as the product of the density times the local acceleration of gravity, so in our case:

Specific weight = 0.791 * 980 = 775 g /(cm^2 s^2)

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