A negative charge of -3.0 x 10^-5 C is placed 0.35 m from a positive charge of 9.0 x 10^-5 C. What is the force between the two charges

the force between the two charges is 198.37 N

Explanation:

Given;

charge of the first particle, Q₁ = -3 x 10⁻⁵ C

charge of the second particle, Q₂ = 9.0 x 10⁻⁵ C

distance between the two charges, r = 0.35 m

The force between the two charges is calculated from Coulomb's law;

where k is Coulomb's constant = 9 x 10⁹ Nm²/C²

Therefore, the force between the two charges is 198.37 N

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2

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