A rocket is fired at 60 to the horizontal with an initial speed of 200m5 calculate it time of flight and it range on the horizontal plane

See answer below

Explanation:

In order to do this, we just need to apply the expression to determine the time of flight. This is given by:

t = 2 V₀ Sinθ / g   (1)

We have the initial speed which is 200 m/s, the angle of elevation to the horizontalis 60° and the gravity is 9.8 m/s². Replacing this data in the above expression we have:

t = 2 * 200 Sin60° / 9.8

Now that we have the time, we can determine the range or distance in the horizontal plane. This can be calculated using the following expression:

X = V * t   (2)

We already have the time, which is the time of flight, the initial speed using cos 60° (Cause it's horizontal plane), and replacing we have:

X = 200 cos60° * 35.348

X = 100 * 35.348

Hope this helps

a. is the answer because they are not shared

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.