A block with mass 20 kg is sliding to the right up a 10° inclined plane with coefficient of kinetic friction 0.4 at a speed of 2 m/s to the right (positive x-direction) How far does it go up along the plane before it comes to rest momentarily? O a 0.36 m O b.0.43 m O c.0.51 m O d. 0.72 m O e.0.81 m​

Full change in the electric plus system

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2