WILL MARK BRAINLIEST FOR THE CORRECT ANSWER AND EXPLANATION When traveling at top speed, a roller coaster train with a mass of 12,000 kg has a velocity of 30 m/s. The kinetic energy of the train at top speed is
J.
Given this kinetic energy, what is the tallest hill this roller coaster train can reach the top of?
The train can climb a hill that is
m. high.

Kinetic energy = 5400000 J

Height, h = 45.91 m

Explanation:

It is given that,

Mass of the roller coaster train, m = 12,000 kg

Velocity of the train, v = 30 m/s

Kinetic energy is given by :

KE=\dfrac{1}{2}mv^2KE=

2

1

mv

2

KE=\dfrac{1}{2}\times 12000\ kg\times (30\ m/s)^2KE=

2

1

×12000 kg×(30 m/s)

2

KE=5400000\ JKE=5400000 J

So, the kinetic energy of the train at the top speed is 5400000 J.

For height

According to law of conservation of energy :

PE_i+KE_i=PE_f+KE_fPE

i

+KE

i

=PE

f

+KE

f

0+5400000\ J=mgh+00+5400000 J=mgh+0

5400000\ J=mgh5400000 J=mgh

h is the height.

5400000\ J=12000\ kg\times 9.8\ m/s^2\times h5400000 J=12000 kg×9.8 m/s

2

×h

h=45.91\ mh=45.91 m

Hence, this is the required solution.

the temperature in kelvin of 2.0 dm3 of an ideal gas is doubled and its pressure is increased by a factor of four. what is the final volume of the gas

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2