What is the centripetal force needed to keep a 3.0 kg mass moving in a circle of radius 0.50 m at a speed of 8.0 m/s

Centripetal acceleration = v²/r = 8²/0.50 = 64/0.50 = 32

Centripetal force = mass * acceleration = 3 * 32 = 96 Newton

So, your answer is 96 Newton

Answer : The centripetal force needed is, 384 N

Solution :

Formula used for centripetal force is,

where,

= centripetal force

m = mass of an object = 3 Kg

r = radius of path

v = velocity or speed of an object

Now put all the given values in the above formula, we get the centripetal force.

Therefore, the centripetal force needed is, 384 N

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.