If a 2 kg ball is moving at 6 m/s to the right and then hits a wall and bounces back at - 4 m/s (left), what is the change in momentum (in kg*m/s)?

Explanation:

Givens

delta mv = ?

m = 2 kg

vi = 6 m/s   right is positive

vf = - 4 m/s  left

Formula

delta mv = m (vf - vi)

Solution

delta mv = 2 * (-4 - 6)

delta mv = 2 * - 10

delta mv = - 20 kg m/s

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.