Ja , Daniel and Helen are pulling a metal ring. Ja pulls with a force of 100N in one direction and Daniel with a force of 140N in the opposite direction. If the ring doesn't move. What force does Helen exert if she pulls in the same direction as Ja.

40N

Explanation:

Given that Ja , Daniel and Helen are pulling a metal ring. Ja pulls with a force of 100N in one direction and Daniel with a force of 140N in the opposite direction. If the ring doesn't move. What force does Helen exert if she pulls in the same direction as Ja ?

Since the ring does not move, that means the forces are in equilibrium.

That is, sum of the forces is equal to zero.

Since Helen is also pulling in the direction of ja, let Helen force be equal to F. The equilibrium of forces among ja, Helen and Daniel can be expressed as:

F + 100 - 140 = 0

That is,

F + 100 = 140

Make F the subject of formula

F = 140 - 100

F = 40N.

Therefore, the force Helen exert if she pulls in the same direction as Ja is 40N.

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14