PLS PLS PLS SOMEONE HELP ME LOL Use your own words and complete sentences to apply Newton’s third law of motion to the action of hitting a golf ball with a golf club.

Make sure to identify the action-reaction force pair and describe the strength of the action force compared to the strength of the reaction force.

Jack Nicklaus once said about golf that "hitting a perfectly straight shot with a big club is a fluke." Science of Golf (SOG): Newton’s Third Law of Motion and Momentum explains what happens when a golfer swings a golf club and applies a big force to the small golf ball. The video features amateur golfer and Stanford University student Patrick Rodgers who gives his opinion on the importance of knowing what causes power and speed in the golf swing. Jim Hubbell, research engineer at the United States Golf Association (USGA) discusses what forces are and how they work in pairs. Hubbell also defines momentum and how it is transferred to the ball.

Hope this helps

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s