You are rereading your notes from class about resolving vectors, but some parts are not making sense. It is apparent that there are some mistakes in your notes. Select all the mistakes. 1.Suppose that we are given a vector with magnitude M and angle g.
2.To resolve a vector into its horizontal and vertical components, we first diagram the vector as the hypotenuse of an isosceles triangle.
3.The angle given is put at the bottom left corner of the triangle.
4. We calculate the vertical component as M sin g. We calculate the horizontal component as M arcsin g.
5.We have to be careful with the trigonometric functions and be sure that our values are for degrees or radians according to how the angle g is given.

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Explanation:

(The second sentence is incorrect because the triangle should be a right triangle, not an isosceles one. The fifth sentence is incorrect because we use M cos g to calculate the horizontal component.)

What are you trying to ask?

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s