Anet force of magnitude 36n gives an object

In working toward the complete solution of this problem, 
I'm going to use addition, subtraction, multiplication, and 
division.  Also, I think I'll be using Newtons 2nd law of motion 
like at least fifteen times, so I'll write it here for our review:  

                                 Force = (mass) x (acceleration). 

-- When 36 N of force acts on m₁ it accelerates at 6 m/s² .

                                             36 N = (m₁) x (6 m/s²)

Divide each side by  6 m/s² :    m₁ = (36 N) / (6 m/s²) = 6 kg .  

-- The same force acting on (m₁+m₂) accelerates them at 2 m/s² .

                                             36 N = (6kg + m₂) x (2 m/s²)

Divide each side by  2 m/s² :    6kg + m₂ = (36N) / (2m/s²) = 18 kg

Subtract  6kg  from each side:            m₂ = 12 kg .

-- The same net force acts on  m₂  alone:

                                             36 N = (12 kg) x (acceleration)

Divide each side by  12 kg :    Acceleration = (36 N) / (12 kg) = 3 m/s² .

Hope this helps alot

1.state2.trash3.the earth

The best description is: . nobody has any idea what q is.