If 100 grams of water is to be heated from 24.0°C to 100.0°C to make a cup of tea, how much heat must be absorbed? The specific heat of water is 4.184 J/g∙°C Solve the problem and show your work.

76*

Explanation:

Q= 31,798.4

Explanation:

You would use the specific heat formula which is Q=mCΔt

m(mass)=100

C(Specific heat capacity)= 4.184

Δt(change in temperature)=24-100=-76 or just 76 in this case

so Q=(100)(4.184)(76)=

418.4(76)=31,798.4

Therefore the missing value Q(heat lost or gained) equal 31,798.4

Hope that helped! xoxo

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.