Determine the increase in volume of 100m3 of mercury when it's temperature change from 10c to 45c the linear expansion coefficient is 6 x 10-5

0.63m

Explanation:

Volume expansivity = change in volume/original volume×temp change

Volume expansivity p = 3x

p = ∆V/V∆t

x is the linear expansivity

Given

x = 6 x 10^-4

p = 3x

p = 3(6 x 10^-5)

p = 18×10^-5

Volume = 100m³

∆t = 45-10 = 35°C

Required

Change in volume ∆V

Substitute the given values into the formula

18×10^-5 = ∆V/100(35)

18×10^-5 =∆V/3500

∆V = 3500×0.00018

∆V = 0.63m

Hence the increase in volume of the Mercury is 0.63n

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