The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force Fsm that the sun exerts on the moon is perpendicular to the force FEM that the earth exerts on the moon. The masses are: mass of sun = 1.99 % 1030 kg, mass of
earth = 5.98 x 1024 kg, mass of moon = 7.35 x 1022 kg. The distances shown in the drawing are rsm = 1.50 x 1011 m and rem = 3.85 x
108m. Determine the magnitude of the net gravitational force on the moon.

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

Ithink the answer is c. make unnecessarily  wide gestures