Determine the magnitude of the gravitational force (in nano-Newton's, i. e. 10^-9N) between a 61.6 kg girl and a 71.2 kg boy standing 95 m apart from one another.

3.24×10¯² nN

Explanation:

From the question given above, the following data were obtained:

Mass of girl (M₁) = 61.6 kg

Mass of boy (M₂) = 71.2 kg

Distance apart (r) = 95 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force (F) =?

The force of attraction between the girl and the boy can be obtained as follow:

F = GM₁M₂ /r²

F = 6.67×10¯¹¹ × 61.6 × 71.2 / 95²

F = 6.67×10¯¹¹ × 61.6 × 71.2 / 9025

F = 3.24×10¯¹¹ N

Finally, we shall convert 3.24×10¯¹¹ N to nN. This can be obtained as follow:

1 N = 10⁹ nN

Therefore,

3.24×10¯¹¹ N = 3.24×10¯¹¹ N × 10⁹ nN / 1 N

3.24×10¯¹¹ N = 3.24×10¯² nN

Thus, the force attraction between the girl and the boy is 3.24×10¯² nN

d.7.5cm is your answer

where’s the list ? the question is incomplete