An object is attached to the lower end of a 100-coil spring that is hanging from the ceiling. The spring stretches by 0.150 m. The spring is then cut into two identical springs of 50 coils each. Each spring is attached between the ceiling and the object. By how much does each spring stretch?

0.125m

Explanation:

Given that:

Length of spring = 100m

Extension, e = 0.250

Recall :

F = ke - - - - (1)

Therefore, if spring is cut into 2 halves :

Then,

k = k1 + K2 ; since k1 and K2 are of equal length

Extension = e'

k = 2k

F = ke'

Then,

F = 2ke' - - - - - (2)

Equate (1) and (2)

ke = 2ke'

e = e'

0.250 = 2e'

0.250 / 2 = e'

e' = 0.125m

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

i will answer your question if you answer mine