A trough is 7 meters long, 2 meters wide, and 1 meters deep. The vertical cross-section of the trough parallel to an end is shaped like an isoceles triangle (with height 1 meters, and base, on top, of length 2 meters). The trough is full of water (density 1000 kg m 3 ). Find the amount of work in joules required to empty the trough by pumping the water over the top. (Note: Use g

68600Nm

Explanation:

Given that:

Lenght, L = 7

Width, W = 2

Depth, d = 1

Triangle = with height 1 meters, and base, on top, of length 2 meters

Area of triangle = 0.5 * base * height

Area of triangle = 0.5 * 2 * 1 = 1m²

Volume = area * length

Volume = 1m² * 7m

Volume = 7m³

Weight of water = Volume * density * g

g = acceleration due to gravity

Density of water , d = 1000kg/m³

Weight = 7m³ * 1000kg/m³ * 9.8m/s²

Weight = 68,600 Kgm/s² = 68600 N

Workdone = Force * distance = weight * depth

Workdone = 68600N * 1m

Workdone = 68600Nm

anchor = archer //

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge