Physics, 05.02.2021 21:30 avasteinhebel10
An 80-kg clown sits on a 20-kg bike on a tightrope attached between two trees. The center of mass of the clown is 1.6 m above the rope, and the center of mass of the bike is 0.70 m above the rope.
A) A load of what mass should be fixed onto the bike and hang 2.10 m below the rope so that the center of mass of the clown-bike-load system is 0.50 m below the rope?
B) What is the force that the rope exerts on each tree if the angle between the rope and the horizontal is 15 (degrees)?
Note: I have tried the center of mass formula Xcm= [(m1*x1) + (m2*x2) + (m3*x3)]/(m1+m2+m3) with no luck. Any help is much appreciated.
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An 80-kg clown sits on a 20-kg bike on a tightrope attached between two trees. The center of mass of...
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