Determine the final velocity of a proton that has an initial velocity of 2.35 x 10^5 m/s and then is accelerated uniformly in an electric field at a rate of –1.10 x 10^12 m/s/s for 1.50 x 10^-7 s. a 7.00 x 10 ^ 3 m/s
b 7.00 x 10 ^ 4 m/s
c 7.00 x 10 ^ 5 m/s
d 7.00 x 10 ^ 6 m/s

b. 7.0 x 10⁴ m/s

Explanation:

Acceleration is defined as the rate of change of velocity with time.

a= v₂-v₁ / t

a= -1.10 x 10¹² m/s²    

v₁ = 2.35 x 10⁵ m/s

v₂ = ?

t= 1.50 x 10⁻⁷ s

Applying the values to the equation

a=v₂-v₁ / t

-1.10 x 10¹² =v₂ - 2.35 x 10⁵ / 1.50 x 10⁻⁷

-1.10 x 10¹² * 1.50 x 10⁻⁷ = v₂ - 2.35 x 10⁵

-1.65 x 10⁻⁵ = v₂ - 2.35 x 10⁵

-1.65 x 10⁻⁵ + 2.35 x 10⁵ = v₂

7.0 x 10⁴ m/s = v₂

which piece of furniture will have the most inertia and give the furniture movers the most difficulty in moving?  

answer

a 75kg dining table

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards