PLEASE HELP THIS IS DUE TOMORROW determine the quantity of work done when a crane lifts a 200-n block from 2 m above the ground to 6 m above the ground

800 joules

Explanation:

In physics, work is defined as

F = W x d (change)

Where  is the word done,  is the force that move the object and  is the change of the position of the object.

In this case, we have

F = 200 N

d= 6m - 2m = 4m , remember that the difference refers to the actual subtraction between the final point and the initial point of the object.

Replacing these values, we have

W = 200 N x 4m

W = 800 joules

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered