A golfer collected data on the distance a golf cart traveled in a straight line and plotted it on a graph Which of these does NOT describe the cart’s motion on this graph?
The cart was at rest between 5 s and 7 s.
The cart moved toward the starting point between 7 s and 12 s.
The cart moved away from the starting point between 8 s and 10 s.
The cart moved away from the starting point between 2 s and 5 s.

The cart moved away from the starting point between 8 s and 10 s.

Explanation:

Given that :

Which of these does NOT describe the cart’s motion on this graph?

The cart was at rest between 5 s and 7 s : From the distance of golf cart Vs time graph ; the car was at rest between 5s and 7s as the graph was flat with that time interval, meaning there was no change in distance.

The cart moved toward the starting point between 7 s and 12 s. : The graph depicts a negative slope at this time interval as the distance from starting point fell from about 26 m to 10 m

The cart moved away from the starting point between 8 s and 10 s. : At this time interval, the cart moved towards the starting not and not away. This could be seen in the decrease in Distance from starting point between the tune interval.

The cart moved away from the starting point between 2 s and 5 s. - - > The cart moved away from the starting point, with the positive slope signifying an increase in distance.

Therefore, The cart moved away from the starting point between 8 s and 10 s does not describe the motion of the cart on the graph.

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures