A 136 kg defensive lineman is about to tackle a 100 kg quarterback. Right before impact, the lineman is moving north at 6.0 m/s and the the quarterback is moving north at 1.0 m/s. Determine the speed and direction of the two players immediately after the tackle.

Explanation:

We shall apply law of conservation of momentum .

Momentum before impact = momentum after impact

Since they are moving towards the same direction , their momentum will add up .

Total momentum before impact

= 136 x 6 + 100 x 1 = 916 kg m/s .

Total mass of lineman and quarterback = 236 kg , if their velocity after impact be v

their momentum = 236 v

According to law of conservation of momentum

236 v = 916

v = 3.88 m /s

Both of them will move with velocity of 3.88 towards the north .

i was thinking more like reflects green light, just not sure

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong