How many electrons are needed to form a charge of -9.10 nC?

5.6875 × 10^(10) electrons

Explanation:

To some this we will use the formula;

q = ne

Where;

q is charge

n is number of electrons

e is electron charge = 1.6 × 10^(-19) C

We are given q = -9.10 nc

1 nc = 10^(-9) C

Thus;

q = -9.1 × 10^(-9) C

Since q is negative, then e = -1.6 × 10^(-19) C

Thus;

-9.1 × 10^(-9) = n(-1.6 × 10^(-19))

n = -(9.1 × 10^(-9))/(-1.6 × 10^(-19))

n = 56875000000 electrons = 5.6875 × 10^(10) electrons

where's the following? you gotta add it to know what the choices are

explanation:

ill do it for 100, also this isnt 80 its 40