14. A 2.5 kg object is experiencing a net force of 50 N while traveling in a circle at a velocity of 5.0 m/s. What is the radius of its motion?

1.25 meters

Explanation:

Given data

Mass= 2.5kg

Force= 50N

velocity= 5m/s

r=

Applying the formula

F= mv^2/r

Make r subject of formula

r= mv^2/F

r= 2.5*5^2/50

r= 2.5*25/50

r=62.5/50

r=1.25 meters

Hence the radius is 1.25 meters

explanation: magnetic pole, region at each end of a magnet where the external magnetic field is strongest. the south-seeking pole, or any pole similar to it, is called a south magnetic pole. unlike poles of different magnets attract each other; like poles repel each other.

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures