Jimothy is riding his bike to his friend's house. He decides to see how fast he can go, and starts pedaling as hard as he can. He began with an initial velocity of 2.5 m/s. He pedals with an acceleration of 1.5 m/s^2 for a time of 6 seconds. Calculate his final velocity.

Final velocity, V = 11.5m/s

Explanation:

Given the following data;

Initial velocity, U = 2.5m/s

Acceleration, a = 1.5m/s²

Time, t = 6secs

To find the final velocity, we would use the first equation of motion

V = U + at

Substituting into the equation, we have

V = 2.5 + 1.5*6

V = 2.5 + 9

Final velocity, V = 11.5m/s

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach