After an initial race George determines that his car loses 35 percent of its acceleration due to air resistance travelling at 38 m/s on flat ground. Assuming that his car travels with a constant acceleration, calculate the maximum speed (Vm), in meters per second, his car can reach on flat ground?\

The maximum velocity of the car at constant acceleration on the road will be 62.2 m/s.

The air resistance is directly proportional to the square of the velocity of an object.

R ∝ v²

The speed of the car was reduced by 35 % at 38 m/s.

So, the speed of the car was reduced by 100% at v' m/s.

The relationship can be given by,

Put the values in the formula and calculate for ,

Therefore, the maximum velocity of the car at constant acceleration on the road will be 62.2 m/s.

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64.2 m/s

Explanation:

We are given that

Speed ,v=38 m/s

We have to find the maximum speed when his car reach on flat ground.

Using dimensional analysis

If 35% acceleration reduced by F(res) at 38 m/s

Then, 100% acceleration  can be reduced  by F(res) at v' m/s

Substitute the values

Hence, the maximum speed when his car can reach on flat ground=64.2 m/s

answer; how far out of place which the object finished relative to the starting location;