A car which is traveling at a velocity of 1.6 m/s undergoes an acceleration of 9.2 m/s over a distance of 540 m. How fast is it going after that acceleration?

Vf = 99.7 m/s

Explanation:

In order to find the final velocity of the car, we will use the third equation of motion. The third equation of motion is given as follows:

where,

a = acceleration of the car = 9.2 m/s²

s = distance traveled by the car = 540 m

Vf = Final Speed of the car = ?

Vi = Initial Speed of the car  1.6 m/s

Vf = 99.7 m/s

answer: he got 23

explanation:

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