In the picture to the right, find the angle at which
the box is pulled if the work done is 50J

42 °

Explanation:

From the question given above, the following data were obtained:

Force (F) = 45 N

Workdone (Wd) = 50 J

Distance (d) = 1.5 m

Angle (θ) =.?

Angle at which the box is pulled can be obtained as:

Wd = Fd × Cos θ

50 = 45 × 1.5 × Cos θ

50 = 67.5 × Cos θ

Divide both side by 67.5

Cos θ = 50 / 67.5

Cos θ = 0.7407

Take the inverse of Cos

θ = Cos¯¹ 0.7407

θ = 42.2 ≈ 42 °

Thus, the angle at which the box is pulled is approximately 42 °.

mass and volume are the answers you are looking for

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .