50 j of work was performed in 20 seconds. How much power was used to preform this task

Power = 2.5 [W]

Explanation:

To be able to solve this problem we must remember that power is defined as the relationship of the work done in a given time interval.

where:

P = power [W] (units of watts)

W = work = 50 [J]

t = time = 20 [s]

Now replacing:

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft