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Physics, 25.01.2021 21:10 mariahisawsome1

The height above the ground of a stone thrown upwards is given by s(t), where t is measured in seconds. After 1secondnothing, the height of the stone is 47feet above the ground, and after 1.5seconds, the height of the stone is 54feet above the ground. Evaluate s(1)and s(1.5),and then find the average velocity of the stone over the time interval [1,1.5].

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