A 9800 N car traveling at 22 m/s strikes a concrete bridge support and comes to a complete halt in 0.5 sec. (This only counts as one problem.) Determine the magnitude of the force acting on the car. Suppose a barrier, which contained material that is gradually crushed during impact so that the stopping time was increased to 3 s, had surrounded the bridge support. What would be the magnitude of the new force

43955.12N and 7325.85N

Explanation:

Step one:

Given data

Weight of car= 9800N

therefore the mass of the car is

w=mg

m= w/g

m= 9800/9.81

m= 998.98 kg

Speed= 22m/s

duration of impact= 0.5 seconds

we know that

impulse, Ft= mv

F= mv/t

F= 998.98*22/0.5

F=21977.56/0.5

F=43955.12N

Hence the force is 43955.12N

if the time is 3 seconds

then the force will be

F= mv/t

F= 998.98*22/3

F=21977.56/3

F=7325.85N

ammonium chloride & tallow

v=ir = 3x15 =45 v