In the figure particles 2 and 4, of charge –e, are fixed in place on a y axis, at y2 = -11.7 cm and y4 = 5.85 cm. Particles 1 and 3, of charge –e, can be moved along the x axis. Particle 5, of charge +e, is fixed at the origin. Initially particle 1 is at x1 = -11.7 cm and particle 3 is at x3 = 11.7 cm. (a) To what x value must particle 1 be moved to rotate the direction of the net electric force F net on particle 5 by 30 ˚ counterclockwise? (b) With particle 1 fixed at its new position, to what x value must you move particle 3 to rotate back to its original direction?

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

conduct current i mean it makes sense