A force is 10 and is used to move a box. It is moved a distance of 3 m. What is the work involved in moving the box?

Workdone = 30Nm

Explanation:

Given the following data;

Force = 10N

Distance = 3m

To find the workdone;

Workdone = force * distance

Substituting into the equation, we have

Workdone = 10 * 3

Workdone = 30Nm.

Therefore, the work involved in moving the box is 30 Newton-meter.

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)