A force, 10 N drags a mass 10 kg on a horizontal table with an acceleration of 0.2 m/s2. If the acceleration due to gravity is 10 m/s2, the coefficient of friction between
the moving mass and the table is?

20&£+)##&843&()-_££-()&_2+0&&-£_!)

all of the answers are correct.

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explanation:

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s