How much force is necessary to stretch a spring 0.5 m when the spring constant is 190 n/m?

Answer

Force is necessary to stretch a spring 0.5 m when the spring constant is 190 N/m is 95 N .

Explanation:

By using Hookes law .

The force required to extend a spring is directly proportional  to the distance you stretch it .

Thus

F = kx

Where F is force , k is spring constant and x is the extension of spring .

As given

A spring is stretch to 0.5 m .

The spring constant is 190 N/m .

x = 0.5 m

k = 190 N /m

Putting all the values in the formula

F = 190 × 0.5

  = 95 N

Therefore the force is necessary to stretch a spring 0.5 m when the spring constant is 190 N/m is 95 N .

b

explanation:

v=ir = 3x15 =45 v