A soccer player is running to the right at 3.2m/s when a 0.50kg ball travelling at 5.0 m/s to the left collides their 5.0kg head. If the player's head velocity after the collision is 2.5 m/s to the right, what is the new velocity of the ball?

300 m/s

Explanation:

Step one:

Given data

Mass of players head m1= 5kg

The initial velocity of players head u1= 3.2m/s

mass of ball m2= 0.5kg

Initial velocity of ball= 5 m/s

Final velocity of player= 2.5 m/s

Required

The velocity of the ball after collision

Step two:

Applying the conservation of momentum formula for elastic collision

m1u1+m2u2= m1v1+m2v2

substitute

5*32+0.5*5= 5*2.5+0.5*v2

160+2.5= 12.5+0.5v2

collect like terms

162.5-12.5= 0.5v2

150= 0.5v2

divide both sides by 0.5

v2= 150/0.5

v2=300 m/s

The new velocity of the ball is 300 m/s

the higher the current the higher the mag field around it the higher the influence on the compass

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)