You drop a coin off of a building and in lands flat on the ground. It hits with a pressure of 200N/m2. It has a weight of 0.1N. What is the area of the coin?

5×10¯⁴ m².

Explanation:

From the question given above, the following data were obtained:

Pressure (P) = 200 N/m²

Weight = Force (F) = 0.1 N

Area (A) =?

Pressure, force and area are related by the following equation:

Pressure (P) = Force (F) / Area (A)

P = F / A

With the above formula, we can obtain the area of the coin as follow:

Pressure (P) = 200 N/m²

Weight = Force (F) = 0.1 N

Area (A) =?

P = F / A

200 = 0.1 / A

Cross multiply

200 × A = 0.1

Divide both side by 200

A = 0.1 / 200

A = 5×10¯⁴ m²

Thus, the area of the coin is 5×10¯⁴ m².