A 1.40-kg ball bounces off a vertical wall. The ball approaches the wall at 9.70 m/s to the east and leaves the wall with the same speed. What is the change in momentum that the wall imparts to the ball

The change in momentum is 0

Explanation:

Step one:

given data

mass of ball = 1.4kg

initial velocity of ball u = 9.7m/s

final velocity of ball v = 9.7m/s

Required

the change in momentum

Step two:

From the expression for momentum

P=mv

the change in momentum

Δp= mu-mv

Δp= 1.4*9.7-1.4*9.7

Δp= 13.58-13.58

Δp=0

There is no change in momentum

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete