Physics, 21.01.2021 16:50 jfleming733

A baseball player throws a baseball with the same initial velocity 5 different times. Each time the ball is thrown at a different angle. The angles are: 45o, 15o, 60o, 25o, and 80o. (a) List the angles based on the amount of time in the air, from the shortest time to the longest time. (b) List the angles based on the horizontal range the baseball travels from the shortest distance to the longest distance.

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Answer from: iPlayOften3722

(a) The list of angles based on amount of time in the air; 15° < 25° < 45° < 60°, < 80°

(b) The list of angles based on distance = 80° < 15° < 25° < 60° < 45°

Explanation:

(a) The given parameters are;

The angles in which the ball is thrown, θ = 45°, 15°, 60°, 25°, and 80°

The velocity with which the ball is thrown each time = The same velocity

The amount of time the projectile is in the air given as follows;

$2 \cdot t = \dfrac{2\cdot u \cdot sin (\theta) }{g}$

Where;

t = Half the amount of time the projectile is in the air

θ = The angle of flight of the projectile

u = The initial velocity of the projectile = Constant for all angles in which the ball is thrown

g = The acceleration due to gravity = 9.8 m/s² = Constant

Therefore, we have;

When θ = 45°;

$2 \cdot t = \dfrac{2\cdot u \cdot sin (45^ {\circ}) }{g} = \dfrac{2\cdot u \cdot \dfrac{\sqrt{2} }{2} }{g} = \dfrac{\sqrt{2} \cdot u }{g}$

When θ = 15°;

$2 \cdot t = \dfrac{2\cdot u \cdot sin (15^ {\circ}) }{g} \approx \dfrac{0.517638\cdot u }{g}$

When θ = 60°;

$2 \cdot t = \dfrac{2\cdot u \cdot sin (60^ {\circ}) }{g} = \dfrac{2\cdot u \cdot \dfrac{\sqrt{3} }{2} }{g} = \dfrac{\sqrt{3} \cdot u }{g}$

When θ = 25°;

$2 \cdot t = \dfrac{2\cdot u \cdot sin (25^ {\circ}) }{g} = \dfrac{0.8452365\cdot u }{g}$

When θ = 80°;

$2 \cdot t = \dfrac{2\cdot u \cdot sin (80^ {\circ}) }{g} = \dfrac{1.9696155\cdot u }{g}$

Therefore, the list of the angles based on the amount of time in the air from the shortest time to the longest time is given as follows;

List of angles based on amount of time in the air; 15° < 25° < 45° < 60°, < 80°

(b) The horizontal range, R is given as follows;

$R = \dfrac{u^2 \cdot sin(2 \cdot \theta) }{g}$

When θ = 45°

$R = \dfrac{u^2 \cdot sin(2 \times 45 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(90 ^{\circ}) }{g} = \dfrac{u^2 }{g}$

When θ = 15°

$R = \dfrac{u^2 \cdot sin(2 \times 15 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(30 ^{\circ}) }{g} = \dfrac{1}{2} \cdot \dfrac{u^2 }{g} = 0.5 \cdot \dfrac{u^2 }{g}$

When θ = 60°;

$R = \dfrac{u^2 \cdot sin(2 \times 60 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(120 ^{\circ}) }{g} = \dfrac{u^2 }{g} \cdot \dfrac{\sqrt{3} }{2} =0.866025 \cdot \dfrac{u^2 }{g}$

When θ = 25°;

$R = \dfrac{u^2 \cdot sin(2 \times 25 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(50 ^{\circ}) }{g} = \dfrac{0.7660444 \cdot u^2 }{g}$

When θ = 80°

$R = \dfrac{u^2 \cdot sin(2 \times 80 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(160 ^{\circ}) }{g} = \dfrac{0.34202 \cdot u^2 }{g}$

Therefore the list of angles based on the horizontal range the baseball travels from the shortest distance to the longest distance is given as follows;

List of angles based on distance = 80° < 15° < 25° < 60° < 45°.

Answer from: Quest

answer;

d. are made mostly of liquid

explanation;

-the general composition and structure planets includes; they have a thick gas and liquid layer covering a small,solid core. mostly the gases are hydrogen and helium atmosphere and layers of liquid hydrogen. for instance neptune and uranus are examples of the outer planets, they have a core covered by ice and ammonia.

-neptune's atmosphere is hydrogen and helium with a bit of methane so there is no oxygen to breath and the interior is made up of frozen water and ammonia with a rock and iron core. thus, there is no liquid water or solid surface to survive.

Answer from: Quest

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.

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