An object is moving with an initial velocity of 3.3m/s it is subject to a constant acceleration of 3.7 m/s2 for 10 s. How far will it have traveled during the time of its acceleration

218m

Explanation:

Given parameters:

Initial velocity  = 3.3m/s

acceleration  = 3.7m/s²

time   = 10s

Unknown:

How far will it travel during the time of acceleration  = ?

Solution:

We use of the kinematics equations to solve this problem;

          S  = ut  +   at²  

S is the distance

u is the initial velocity

t is the time

a is the acceleration

   So;

            S  = (3.3x10)   +   (  x 3.7 x 10²)  = 218m

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