A hydrogen atom is isolated in a vacuum chamber, the electron is now separated from the proton and moved to a distance 1 cm away. Let Fg be the magnitude of the gravitational force between the proton and electron, and let Fe be the magnitude of the electric force between the proton and electron. How does the ratio Fg/Fe change as the particles are separated

hello your question is incomplete attached below is the complete question

Fg / Fe does not change ; it is the same nonzero value for all separations ( A )

Explanation:

Given that distance between proton and electron is 1 cm

Fg = Gm1m2 / r^2

where :

G ( gravitational constant )= 6.67 * 10^-11 Nm^2 / kg^2

m1 ( mass of proton ) = 1.67 * 10^-27 kg

m2 ( mass of electron ) = 9.11 * 10^-31 kg

Electrical force

Fe = kq1q2 / r^2

k = 9*10^9

hence ;

Fg / Fe = (Gm1m2 / r^2) / (kq1q2 / r^2 )

            = Gm1m2 / kq1q2

he kicked it 10 feet straight up into the air? i think this works.

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.