Three charges, each separated by 100 m from adjacent charges, are located along a horizontal line: a -3.00 C charge on the left, a 2.00 C charge in the middle, and a 1.00 C charge on the right. What is the resultant force on the 1.00 C charge due to the other two

F= 11.25*10⁵ N to the right.

Explanation:

Assuming that the three charges can be treated like point charges, they must obey Coulomb's Law.Due to the linearity of this Law, we can use superposition in order to find the resultant force on the 1.00 C charge due to the other two.First, we find the force that the -3.00 C charge (located 200 m to the left) exerts on the 1.00 C, as follows:

     

Then, in the same way, we can find the force that the 2.00 C exerts on the 1.00 C charge, located 100 m away to the left:

     

Since both vectors are on the same line, their sum is directly the algebraic sum, as follows:F₃ = F₁₃ + F₂₃ = -6.75*10⁵ N + 18.00*10⁵ N = 11.25*10⁵ N to the right, assuming this direction as positive.