An airplane maintains a speed of 669 km/h relative to the air it is flying through as it makes a trip to a city 675 km away to the north. (a) What time interval is required for the trip if the plane flies through a headwind blowing at 33.0 km/h toward the south

1.06 h

Explanation:

Assuming that the airplane is traveling through the air, moving at a sites relative to the ground. The airplane is expected to make a displacement of 675 km due North.

Let north y be positive, and west x also be positive, then

With the wind blowing at 33 km/h due South. We then say,

The northern component of the velocity of the airplane you the ground is

669 km/h - 33 km/h = 636 km/h

Then, the time interval taken by the airplane to travel 675 km is

675 / 636 = 1.06 h

Therefore, we can conclude that the answer is 1.06 h

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