Two trucks with equal mass are attracted to each other with a gravitational force of 6.7 x 10^-4 N. The trucks are separated by a distance of 3.0 m. What is the mass of one of the trucks?

The mass of one of the trucks is 9510 kg.

The problem above can be solved using the mathematical expression of newton's law of universal gravitation

Using Newton's law of universal gravitation,

F = Gm²/r² Equation 1

Where F = Gravitational force on the truck, m = mass of each truck, r = distance between the trucks, G = universal constant

make m the subject of the equation

m = √(Fr²/G) Equation 2

From the question,

Given: F = 6.7×10⁻⁴ N, r = 3.0 m.

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute these values into equation 2

m = √[(6.7×10⁻⁴×3²)/(6.67×10⁻¹¹)]

m = √(9.04×10⁷)

m = 9.51×10³ kg.

m = 9510 kg

Hence, The mass of one of the trucks is 9510 kg

Learn more about Newtons law of universal gravitation here: link

9508.1kg

Explanation:

Given parameters:

Gravitational force  = 6.7 x 10⁻⁴N

Distance of separation  = 3m

Unknown:

Mass of one of the truck  = ?

Solution:

Let the mass of one of the truck be  = m

According to the Newton's law of universal gravitation:

   Fg  =  

 G is the universal gravitation constant  = 6.67 x 10⁻¹¹

  m1 and m2 are the masses of the two bodies, here m1  = m2  = m

  d is the distance of separation between them

 6.7 x 10⁻⁴   =  

          6.67 x 10⁻¹¹m²   = 9 x   6.7 x 10⁻⁴  

                          m   = 9508.1kg

if the forces acting on an object are unbalanced, the object will accelerate in the direction of the net force on the object.

explanation:

this is best explained by having an understanding of newton's second law, which states that f=ma. you see, when the forces are unbalanced, net force (sum of all forces) is not zero. therefore making it necessary for the object to have an acceleration in the direction of the net force.

its c its is a mixture of gases