Two copper spheres are currently 0.5 meters apart. One sphere has a charge of +3.4x10-4 C and the other has a charge of -5.6*10-4 C. What is the force between
the charged spheres? (k=8.89*10' Nm²/C2)
0 -6839.17 N
0 1200 N
0 5497.45 N
6839.17 N

6839.17 N

Explanation:

From the question given above, the following information were obtained:

Distance apart (r) = 0.5 m

Charge 1 (q₁) = +3.4×10¯⁴ C

Charge 2 (q₂) = -5.6×10¯⁴ C

Electrical constant (K) = 8.98×10⁹ Nm²/C²

Force (F) =.?

F = Kq₁q₂ / r²

F = 8.98×10⁹ × 3.4×10¯⁴ × 5.6×10¯⁴ / 0.5²

F = 1709.792 / 0.25

F = 6839.17 N

Thus, the force of attraction between the two charged spheres is 6839.17 N

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray