A 3 kg block is attached to a spring of spring constant k = 250 N/m. The block is pulled to a maximum distance (amplitude) of 8 cm What is the value of the spring force when the block is at 8 cm?

20 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) of block = 3 Kg

Spring constant (K) = 250 N/m

Extention (e) = 8 cm

Force (F) =?

Next, we shall convert 8 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

8 cm = 8 cm × 1 m / 100 cm

8 cm = 0.08 m

Thus, 8 cm is equivalent to 0.08 m.

Finally, we shall determine the force when the block is at 8 cm (i.e 0.08 m). This can be obtained as follow:

Spring constant (K) = 250 N/m

Extention (e) = 0.08 m

Force (F) =?

F = Ke

F = 250 × 0.08

F = 20 N

Thus, the force is 20 N.

the answer is to check all of them! they all apply well at least i think so!

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.