A 1.0 × 10^3 kg sports car is initially traveling at 15 m/s. The driver then applies the brakes for several seconds so that -25 kJ of net work is done on the car. Calculate the initial and final kinetic energy of the car.

Ea = 112500[J]

Eb = 87500[J]

Explanation:

To solve this problem we must use the principle of energy conservation which tells us that the energy of a body plus the work done or applied by the body equals the final energy of a body.

This can be easily visualized by the following equation:

Now we must define the energies at points A & B.

For point A

At point A we only have kinetic energy since it moves at 15 [m/s]

So the kinetic energy

The final kinetic energy can be calculated as follows:

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explanation:

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