a shower stall measures 86.0 cm x 86.0 cm x 210 cm. When you sing in the shower, which frequencies will sound the riches (because of resonance)

Explanation:

From the given information:

The length of the shower stall L = 86.0 cm = 0.86 m

The width of the shower stall W = 210 cm = 2.1 m

Let assume that the stall acts as a closed pipe and the various singer voices range from 130 Hz to 2000 Hz.

Then; using wavelength equation;

where;

&

∴

By making the resonating frequency f the subject of the above formula, we have:

where;

L = 0.860 m , then n = 1

Thus;

f = 206 Hz

For n = 9

Thus, the resonant frequencies range for n = 1 to 9 with W = 2.10 m

However;

For n = 2

For n = 23

Thus, the resonant frequencies range from n = 2 to n= 23.

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .

this means that the temperature of both substances will be equal